10x^2+8x+50=8x+3650

Solution for 10x^2+8x+50=8x+3650 equation:

10x^2+8x+50=8x+3650

We move all terms to the left:

10x^2+8x+50-(8x+3650)=0

We get rid of parentheses

10x^2+8x-8x-3650+50=0

We add all the numbers together, and all the variables

10x^2-3600=0

a = 10; b = 0; c = -3600;
Δ = b2-4ac
Δ = 02-4·10·(-3600)
Δ = 144000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{144000}=\sqrt{14400*10}=\sqrt{14400}*\sqrt{10}=120\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120\sqrt{10}}{2*10}=\frac{0-120\sqrt{10}}{20}
=-\frac{120\sqrt{10}}{20}
=-6\sqrt{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120\sqrt{10}}{2*10}=\frac{0+120\sqrt{10}}{20}
=\frac{120\sqrt{10}}{20}
=6\sqrt{10}
$